First slide

Vectors

Question

The magnitude of the vector product of two vectors is $\sqrt{3}$ times their scalar product. The angle between the two vectors is

Easy

A

$\frac{π}{2}$
B

$\frac{π}{6}$
C

$\frac{π}{3}$
D

$\frac{π}{4}$

Solution

$\begin{array}{l} | A \times B | = ABsin θ \\ A \cdot B = ABcos θ \end{array}$
Given $ABsin θ = \sqrt{3} ABcos θ$
$∴ \tan θ = \sqrt{3} or θ = 60^{\circ} = π / 3$

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