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The magnitude of the vector product of two vectors is $\sqrt{3}$ times their scalar product. The angle between the two vectors is

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detailed solution

Correct option is C

|A×B|=ABsin⁡θA⋅B=ABcos⁡θGiven ABsin⁡θ=3ABcos⁡θ∴tan⁡θ=3 or θ=60∘=π/3

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The magnitude of the vector product of two vectors is 3 times their scalar product. The angle between the two vectors is

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Ready to Test Your Skills?

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The magnitude of the vector product of two vectors is $\sqrt{3}$ times their scalar product. The angle between the two vectors is