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The magnitude of the vector product of two vectors is $\frac{1}{\sqrt{3}}$ times their scalar product. The angle between the two vectors is

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detailed solution

Correct option is D

Given |A→×B→|=13 A→ . B→ ⇒ ABsinθ=13 ABcosθ ⇒ tanθ=13 ⇒ θ=300

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The magnitude of the vector product of two vectors is 13 times their scalar product. The angle between the two vectors is

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Ready to Test Your Skills?

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The magnitude of the vector product of two vectors is $\frac{1}{\sqrt{3}}$ times their scalar product. The angle between the two vectors is