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The magnitudes of two vectors $\large \vec P$ and $\large \vec Q$ differ by 1. The magnitude of their resultant makes an angle of tan^–1(3/4) with P. The angle between P and Q is

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Correct option is D

(i) P - Q =1(ii)Tan α = 3/4 = Qsinθ /P+Qcosθwhere θ is the angle between P and Q , α is the angle between P and R∴ When θ = 900 can only satisfy both the conditions (i) & (ii)

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The magnitudes of two vectors and differ by 1. The magnitude of their resultant makes an angle of tan–1(3/4) with P. The angle between P and Q is

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Ready to Test Your Skills?

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The magnitudes of two vectors $\large \vec P$ and $\large \vec Q$ differ by 1. The magnitude of their resultant makes an angle of tan^–1(3/4) with P. The angle between P and Q is