First slide

Scalars and Vectors

Question

The magnitudes of vectors $\vec{A}, \vec{B} and \vec{C}$ are 3,4 and 5 units respectively. If $\vec{A} + \vec{B} = \vec{C}$ , the angle between $\vec{A}$ and $\vec{B}$ is

Easy

A

$\frac{π}{2}$
B

$\cos^{- 1} (0.6)$
C

$\tan^{- 1} (\frac{7}{5})$
D

$\frac{π}{4}$

Solution

$\begin{array}{l} C = \sqrt{A^{2} + B^{2}} = \sqrt{3^{2} + 4^{2}} = 5 \\ ∴ Angle between \vec{A} and \vec{B} is \frac{π}{2} \end{array}$

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