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A man can see the object between 15 cm and 30 cm. He uses the lens to see the far objects. Then due to the lens used, the near point will be at

a
10/3 cm
b
30 cm
c
15 cm
d
100/3 cm

detailed solution

Correct option is B

For improving far point, concave lens is required and for this concave lens u = ∞, v = - 30 cmso  1f=1−30−1∞⇒f=−30cmfor  nearpoint  1−30=1−15−1u⇒u=−30cm

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