A man can swim in still water with a speed of 2 ms-1. If he wants to cross a river of water current speed 3ms−1 along the shortest possible path, then in which direction should he swim?

The speed of the man is 2m/s and the speed of the water current is 3m/s.The velocity component acting opposite to that of the velocity of water current is given as,vmsin⁡θ=vr2×sin⁡θ=3θ=60∘The angle between the speed of man and the water current is given as,θ1=60∘+90∘=150∘Thus, the direction of swimming is at an angle 1500 to the water current.