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Motion of planets and satellites

Question

A man can throw a ball at a speed on the earth which can cross a river of width 10 m. The man reaches on an imaginary planet whose mean density is twice that of the earth. Find out the maximum possible radius of the planet (in km) so that if the man throws the ball at the same speed it may escape from the planet. Given radius of the earth = 6.4 x 106 m.

Moderate
Solution

Let the speed of the ball which can cross 10 m wide river be V.

 Then R=V2sin2×45g=10,v=10g

Let the radius of planet be ' Rp', then mass of the planet

Mp=43πRp3×2σ=43πRp3×2×Me4/3πReR=2MeRp3Re3

Escape velocity of the Planet

Ve=2GMpRp=2G×2×MeRp3Rp×Re3=10GMeRe22Rp=10Re2Rp=10×6.4×106 Rp=8×1032=4×103=4km



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