Question

A man can throw a stone such that it acquires maximum horizontal range 80 m. The maximum height to which it will rise for the same projectile (in metre) is

Moderate

Solution

$At θ = 45 °, R_{\max} = \frac{u^{2}}{g} = 80$
$∴ u^{2} = 800 m^{2} s^{- 2}$
Now, $H = \frac{u^{2} \sin^{2} 45 °}{2 g} = \frac{(800) (1 / 2)}{20} = 20 m$

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