A man crosses a 320 m wide river perpendicular to the current in 4 minutes. If in still water he can swim with a speed 5/3 times that of the current, then the speed of the current, in m/min is
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a
30
b
40
c
50
d
60
answer is D.
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Detailed Solution
Resultant velocity of man w.r.t. river, vR=3204=80m/min . Let v be the velocity of river water, the velocity of man =53v ∴ 53v=vR2−v2 or 259v2=802−v2 or 169v2=802 or 43v=80 or v=80×34=60m/min