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Q.

A man drops a ball downside from the roof of a tower of height 400 m. At the same time another ball is thrown upside with speed of 50 ms−1, they will meet at which height from the base of the tower:

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a

100 m

b

320 m

c

80 m

d

240 m

answer is C.

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Detailed Solution

Let both balls meet at point P after time tThe distance travelled by ball A, h1=12gt2The distance travelled by ball B, h2=ut−12gt2 h1+h2=400m⇒ut=400,t= 400/50 = 8 sech1=320m and h2=80m

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A man drops a ball downside from the roof of a tower of height 400 m. At the same time another ball is thrown upside with speed of 50 ms−1, they will meet at which height from the base of the tower: