Plane mirror

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Question

A man of height 2h stands in the middle of room of length 6h. The height of the wall is 4h. The minimum length of plane mirror to be placed on the wall infront of the man so that he can see entire wall behind line is $\frac{x h}{3}$ . The value of x is

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Solution

$\frac{η H}{η + 1} = \frac{\frac{1}{2} (4 h)}{\frac{1}{2} + 1} = \frac{4 h}{3}$

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