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A man is inside a lift. When the lift is moving up with certain acceleration, the apparent change in weight is 50%. When the lift moves down with double the acceleration, the apparent change in weight is

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detailed solution

Correct option is B

Apparent change is weight =ag×100=50 a=g2 If acceleration becomes 2a=2g2=gApparent change in wt = gg×100=100%

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