A man is inside a lift. When the lift is moving up with certain acceleration, the apparent change in weight is25% . When the lift moves down with same acceleration, the apparent change in weight is
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a
25%
b
50%
c
75%
d
40%
answer is A.
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Detailed Solution
ag×100=25 take agx100=∆wwx100 a=g4 % change = a′g×100 = 14×100=25%
A man is inside a lift. When the lift is moving up with certain acceleration, the apparent change in weight is25% . When the lift moves down with same acceleration, the apparent change in weight is