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Q.

A man of 50 kg  is standing at one end on a boat of length 25 m  and mass 200kg . If the starts running and when he reaches the other end, he has a velocity 2 ms−1  with respect to the boat. The final velocity of the boat is : (in ms−1 )

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a

25

b

23

c

85

d

83

answer is A.

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Detailed Solution

Let v be the velocity of the boat with respect to the water, then from conservation of linear momentum. (200+50)v+50×2=50×0+200×0 250v=−100 v=−100250=−25m/s
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