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A man of 50 $k g$ is standing at one end on a boat of length 25 $m$ and mass 200 $k g$ . If the starts running and when he reaches the other end, he has a velocity 2 $m s^{- 1}$ with respect to the boat. The final velocity of the boat is : (in $m s^{- 1}$ )

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Correct option is A

Let v be the velocity of the boat with respect to the water, then from conservation of linear momentum. (200+50)v+50×2=50×0+200×0 250v=−100 v=−100250=−25m/s

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A man of 50 kg is standing at one end on a boat of length 25 m and mass 200kg . If the starts running and when he reaches the other end, he has a velocity 2 ms−1 with respect to the boat. The final velocity of the boat is : (in ms−1 )

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A man of 50 $k g$ is standing at one end on a boat of length 25 $m$ and mass 200 $k g$ . If the starts running and when he reaches the other end, he has a velocity 2 $m s^{- 1}$ with respect to the boat. The final velocity of the boat is : (in $m s^{- 1}$ )