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A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed of 2 . When the stone reaches the floor, the distance of the man above the floor will be
detailed solution
Correct option is B
As there is no external force acing on man, initially the center of mass of the system was at rest hence there is no displacement of center of mass. [m1+m2] ∆rcom=0 m 1∆r1 - m2∆r2 =0⇒ ∆r2 = m1∆r1m2 = 0.5×1050 = 0.1 mThe distance of the man above the floor (total height) = 10+0.1 = 10.1 mTalk to our academic expert!
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