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Q.

A man in a lift feels an apparent weight W when the lift is moving up with a uniform acceleration of 1/3rd of the acceleration due to gravity. If the same man were in the same lift now moving down with a uniform acceleration that is 1/2 of the acceleration due to gravity, then his apparent weight is

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a

3W/8

b

3W/4

c

W/8

d

5W/8

answer is A.

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Detailed Solution

W1=mg+g3 in the first case W2 =mg-g2 in the second case W1W2=4mg3mg2=83
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