First slide
Different types of Forces
Question

A man of mass 60 kg is riding in a lift. The weight of the man when the lift is accelerating upwards and
downwards at 2 ms-2 are respectively (Take, g = 10 ms-2) [AMU 2011] 

Easy
Solution

When the lift is accelerating upwards with a constant acceleration a, then the apparent weight,

w=m(g+a)=60(10+2)

=60×12=720 N

When the lift is accelerating downwards with acceleration a, then apparent weight,

w'=m(g-a)=60(10-2)

=60×8=480 N

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