A man of mass 60 kg is riding in a lift. The weight of the man when the lift is accelerating upwards anddownwards at 2 ms-2 are respectively (Take, g = 10 ms-2) [AMU 2011]

When the lift is accelerating upwards with a constant acceleration a, then the apparent weight,w=m(g+a)=60(10+2)=60×12=720 NWhen the lift is accelerating downwards with acceleration a, then apparent weight,w'=m(g-a)=60(10-2)=60×8=480 N