First slide

Kinetic friction

Question

A man of mass 60 kg sitting on ice pushes a block of mass of 12 kg on ice horizontally with a speed of 5 ms^-1.The coefficient of friction between the man and ice and between block and ice is 0.2. If g =10 ms^-2,the distance between man and the block, when they come to rest is

Moderate

A

6 m
B

6.5 m
C

3 m
D

7 m

Solution

$S_{1} = \frac{v^{2}}{2 μg},$ according to law of conservation of momentum, find $v^{1}; S_{2} = \frac{v^{1^{2}}}{2 μg}; S = S_{1} + S_{2}$

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