A man of mass 60 kg sitting on ice pushes a block of mass of 12 kg on ice horizontally with a speed of 5 ms-1.The coefficient of friction between the man and ice and between block and ice is 0.2. If g =10 ms-2,the distance between man and the block, when they come to rest is
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a
6 m
b
6.5 m
c
3 m
d
7 m
answer is B.
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Detailed Solution
S1=v22μg,according to law of conservation of momentum, find v1; S2=v122μg; S=S1+S2