A man of mass M stands at one end of a plank of length L which lies at rest on a frictionless surface.
The man walks to the other end of the plank. If the mass of the plank is $\frac{M}{3},$ the distance that the man
moves relative to the ground is

Question

Infinity Learn · Accepted Answer

Let plank moves x distance in opposite direction. Then, displacement of man relative to ground will be (L$$ $$-$$ $$x). Applying law of conservation of momentum,           $$mRxRt=mLxLt$$   or   $$M(L-x)=M3xSolving$$ this equation, we get x $$=$$ $$3L4$$∴ Displacement of man relative to ground $$=$$ $$L-3L4=L4$$

A man of mass M stands at one end of a plank of length L which lies at rest on a frictionless surface.
The man walks to the other end of the plank. If the mass of the plank is $\frac{M}{3},$ the distance that the man
moves relative to the ground is

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A man of mass M stands at one end of a plank of length L which lies at rest on a frictionless surface.The man walks to the other end of the plank. If the mass of the plank is M3, the distance that the manmoves relative to the ground is

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Ready to Test Your Skills?

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A man of mass M stands at one end of a plank of length L which lies at rest on a frictionless surface.
The man walks to the other end of the plank. If the mass of the plank is $\frac{M}{3},$ the distance that the man
moves relative to the ground is