Questions
A man measure the period of a simple pendulum inside a stationary lift and finds it to be T seconds. If the lift accelerates upwards with an accelerating g/4, then the period of the pendulum will be
detailed solution
Correct option is C
in stationary lift T=2πlg ------(1)In upward motion of liftT1=2πlg+a-----(2) here a is acceleration of liftdivide equation (2) by (1)T1T=gg+a=gg+g/4 given a=g/4→T1T=45=25cross multiply, to obtain new time period of simple pendulum⇒T1=2T5.Talk to our academic expert!
Similar Questions
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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