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A man measure the period of a simple pendulum inside a stationary lift and finds it to be T seconds. If the lift accelerates upwards with an accelerating g/4, then the period of the pendulum will be

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a
T
b
T4
c
2T5
d
2T5

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detailed solution

Correct option is C

in statonary lift  T=2πlg---(1) In upward motion of lift  T1=2πlg+a---(2) dividing eqn(2) by eqn(1) T1T=gg+a given a=g4 T1T=gg+g4  T1T=45=25 T1=2T5 -


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