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A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. If the lift accelerates upwards with an acceleration g/4 , then the period of the pendulum will be 

a
T
b
T4
c
2T5
d
2T5

detailed solution

Correct option is C

In stationary lift  T=2πlgIn upward moving lift  T'=2πl(g+a)(a= Acceleration of lift) ⇒T'T=gg+a=gg+g4=45 ⇒T'=2T5

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