For a man moving on track ABC, rain drops appear to fall vertically for the path AB, and along the same line of its motion (i.e., as observed by a stationary observer) for path BC. The actual speed of rain drop is (in m/s)

[Step 1]:  VR=Vxi+Vyj[Step 2]: For path AB  Vx=5ms−1[Step 3]: For path BC velocity of rain  ⊥r to BC should be zero hence[Step 4]: VX sin300=Vycos300​5×12=Vy×32​⇒Vy=53ms−1[Step 5]:    VR=VX2+VY2=52+532=25+253=103ms−1=5.77ms−1