Questions
A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is 340ms-1, the distance between the cliffs is
detailed solution
Correct option is A
Total time taken for both the echoes t=t1+t2=2secbut t=2d1v+2d2v⇒t=2vd1+d2⇒(d1+d2)=v×t2=340×22=340mTalk to our academic expert!
Similar Questions
A man is standing between two parallel cliffs and fires a gun. If he hears first and second echoes after 1.5 s and 3.5s respectively, the distance between the cliffs is (Velocity of sound in air = 340 ms–1)
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