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Q.

A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is 340ms-1, the distance between the cliffs is

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a

340 m

b

1620 m

c

680 m

d

1700 m

answer is A.

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Detailed Solution

Total time taken for both the echoes t=t1+t2=2secbut t=2d1v+2d2v⇒t=2vd1+d2⇒(d1+d2)=v×t2=340×22=340m
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