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Q.

A man is standing between two parallel cliffs and fires a gun. If he hears first and second echoes after 1.5 s and 3.5s respectively, the distance between the cliffs is (Velocity of sound in air = 340 ms–1)

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a

1190 m

b

850 m

c

595 m

d

510 m

answer is B.

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Detailed Solution

2d1+2d2=v×t1+v×t2⇒2(d1+d2)=v(t1+t2)d1+d2=v(t1+t2)2=340×(1.5+3.5)2=850 m
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