First slide

Reflection and refraction of waves

Question

A man is standing between two parallel cliffs and fires a gun. If he hears first and second echoes after 1.5 s and 3.5s respectively, the distance between the cliffs is (Velocity of sound in air = 340 ms^–1)

Moderate

A

1190 m
B

850 m
C

595 m
D

510 m

Solution

$2 d_{1} + 2 d_{2} = v \times t_{1} + v \times t_{2} \Rightarrow 2 (d_{1} + d_{2}) = v (t_{1} + t_{2})$
$d_{1} + d_{2} = \frac{v (t_{1} + t_{2})}{2} = \frac{340 \times (1 .5 + 3 .5)}{2} = 850 m$

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