A man is standing on a cart of mass double the mass of the man. Initially, the cart is at rest on the smooth ground. Now man jumps with relative velocity v horizontally towards the right with respect to cart. What will be the work done by the man during the process of jumping?

Question

Infinity Learn · Accepted Answer

Let the velocity of man after jumping be ‘u’ ' towards right. Then speed of cart is v $$-$$ u towards left. From conservation of $$momentummu=2m(v$$  $$u)$$∴$$u=2v3Hence$$ work done by man $$=$$ change in $$KE$$ of $$system=12mu2+122m(v-u)2=12m2v32+122mv32=mv23$$

A man is standing on a cart of mass double the mass of the man. Initially, the cart is at rest on the smooth ground. Now man jumps with relative velocity v horizontally towards the right with respect to cart. What will be the work done by the man during the process of jumping?

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