Q.

A man standing at the centre of a turn table which is rotating at an angular velocity of 10 rad/s, with its arms out stretched. He suddenly folds his arms. If the moment of inertia of the turn table is 2.5 kg−m2, moment of inertia of the man with stretched arms is 0.3 kg−m2 and moment of inertia of the man with folded arms is 0.1 kg−m2, then final angular velocity of the turn table is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

11.22 rad/s

b

10.05 rad/s

c

10.77 rad/s

d

12.77 rad/s

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Conserving angular momentum 2.5+0.1ω=2.5+0.3×10⇒ω=2.8×102.6rad/s=10.77 rad/s
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon