Q.
A man standing at the centre of a turn table which is rotating at an angular velocity of 10 rad/s, with its arms out stretched. He suddenly folds his arms. If the moment of inertia of the turn table is 2.5 kg−m2, moment of inertia of the man with stretched arms is 0.3 kg−m2 and moment of inertia of the man with folded arms is 0.1 kg−m2, then final angular velocity of the turn table is
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a
11.22 rad/s
b
10.05 rad/s
c
10.77 rad/s
d
12.77 rad/s
answer is C.
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Detailed Solution
Conserving angular momentum 2.5+0.1ω=2.5+0.3×10⇒ω=2.8×102.6rad/s=10.77 rad/s
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