A man standing at the centre of a turn table which is rotating at an angular velocity of $$10$$ $$rad/s$$, with its arms out stretched. He suddenly folds his arms. If the moment of inertia of the turn table is $$2.5$$ kg−$$m2$$, moment of inertia of the man with stretched arms is $$0.3$$ kg−$$m2$$ and moment of inertia of the man with folded arms is $$0.1$$ kg−$$m2$$, then final angular velocity of the turn table is

Question

A man standing at the centre of a turn table which is rotating at an angular velocity of $$10$$ $$rad/s$$, with its arms out stretched. He suddenly folds his arms. If the moment of inertia of the turn table is $$2.5$$ kg−$$m2$$, moment of inertia of the man with stretched arms is $$0.3$$ kg−$$m2$$ and moment of inertia of the man with folded arms is $$0.1$$ kg−$$m2$$, then final angular velocity of the turn table is

Infinity Learn · Accepted Answer

Conserving angular momentum $$2.5+0.1$$ω$$=2.5+0.3$$×$$10$$⇒ω$$=2.8$$×$$102.6rad/s=10.77$$ $$rad/s$$

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