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Q.

A man standing on the roof of a house of height h throws one particle vertically downwards and another particle horizontally with the same velocity u . The ratio of their velocities when they reach the earth's surface will be

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a

u2+2gh :u

b

1:2

c

1:1

d

u2+2gh :2gh

answer is C.

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Detailed Solution

for particle projected vertically downwards v2= u2+2gh for the particle projected horizontally horizontal velocity vx= u and vertical velocity vy after a height h is 2gh tolal velocity v=vx2+vy2 v2=u2+2gh

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