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Questions  

A man standing on the roof of a house of height h throws one particle vertically downwards and another particle horizontally with the same velocity  u . The ratio of their velocities when they reach the earth's surface will be

a
u2+2gh :u
b
1:2
c
1:1
d
u2+2gh :2gh

detailed solution

Correct option is C

for particle projected vertically downwards  v2= u2+2gh for the particle  projected horizontally horizontal velocity vx= u and vertical velocity vy  after a height h is 2gh tolal velocity v=vx2+vy2   v2=u2+2gh

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