First slide

Projection Under uniform Acceleration

Question

A man swims from a point A on one bank of a river of width 100 m. When he swims perpendicular to the water current, he reaches the other bank 50 m downstream. The angle to the bank at which he should swim, to reach the directly opposite point B on the other bank is

Moderate

A

10° upstream
B

20° upstream
C

30° upstream
D

60° upstream

Solution

fer to Fig. (a), $tanθ = \frac{v_{w}}{v_{m}} = \frac{50}{100} = \frac{1}{2} of Vm = 2 vw Refer to Fig ., sinα = \frac{v_{w}}{v_{m}} = \frac{V_{w}}{2 v_{w}} = \frac{1}{2}$

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