A man swims from a point A on one bank of a river of width 100 m. When he swims perpendicular to the water current, he reaches the other bank 50 m downstream. The angle to the bank at which he should swim, to reach the directly opposite point B on the other bank is

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10° upstream

20° upstream

30° upstream

60° upstream

answer is D.

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Detailed Solution

tanθ=vwvm=50100=12sinα=vwvm=vw2vw=12or θ= 30°. So, it is 60° upstream.

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