A man throws balls with the same speed vertically upwards one after the other at an interval of $$2$$ seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given$$ $$g=9.8m/s2$$ $$)

Question

A man throws balls with the same speed vertically  upwards one after the other at an interval of $$2$$ seconds. What should be the  speed of the throw so that more than two balls are in the sky at any time?  (Given$$ $$g=9.8m/s2$$     $$)

Infinity Learn · Accepted Answer

Interval of ball $$throw=2sec$$       If we want that minimum three (more$$ than $$two) balls remain in air  then time of flight of first ball must be greater than $$4$$ $$sec$$     , i.e.,T>$$4$$ $$sec$$     Or $$2ug$$>$$4$$ $$sec$$      or u>$$19.6m/s$$     $$Foru=19.6$$     . First ball will just strike the ground (in$$ $$sky), second  ball will be highest point (in$$ $$sky). Third ball will be at the point of  projection or at ground (not$$ in $$sky).

A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given $g = 9.8 m / s^{2}$ )

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A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given g=9.8m/s2 )

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Ready to Test Your Skills?

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A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given $g = 9.8 m / s^{2}$ )