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A man throws the bricks to a height of 12 m where they reach with a speed of 12 m/s, if he throws the bricks such that they just reach that height, what percent of energy will be saved? [g = 10 m/s²]

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Correct option is C

Percentage of energy saved =12mV12−12mV2212mV12×100%=1−V2V12×100%=1−2ghV2+2gh×100%=V2V2+2gh×100%=122122+2×10×12×100%=37.5%

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A man throws the bricks to a height of 12 m where they reach with a speed of 12 m/s, if he throws the bricks such that they just reach that height, what percent of energy will be saved? [g = 10 m/s2]

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A man throws the bricks to a height of 12 m where they reach with a speed of 12 m/s, if he throws the bricks such that they just reach that height, what percent of energy will be saved? [g = 10 m/s²]