Questions
A man turns on rotating table with an angular speed ω. He is holding two equal masses at arms length. Without moving his arms, he just drops the two masses on to rotating table. How will his angular speed change?
detailed solution
Correct option is C
Net external torque on the system is zero. Therefore, angular momentum of the system about the axis of rotation is conserved..: I ω = constant.: I2 ω2 = I1 ω1Let I1 = M.O.I of the system when the man is holding the masses.I 2 = M.O.I of the system when the man drops the masses onto the table.Since, the radial distances of the masses from axis of rotation in both cases are the same, I1 = I2.: ω1 = ω2 = ωSimilar Questions
A disc rotates freely with rotational kinetic energy E about a normal axis through centre. A ring having the same radius but double the mass of disc is now, gently placed on the disc. The new rotational kinetic energy of the system would be
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