A man weighing 60 kg stands on the horizontal platform of a spring balance. The platform starts executing simple harmonic motion of amplitude 0.1 m and frequency $\frac{2}{\pi }\mathrm{Hz}$. Which of the following statement is correct?

detailed solution

Correct option is D

The maximum force acting on the body executing simple harmonic motion ismω2a=m×(2πf)2a=60×2π×2π2×0.1N=60×16×0.1=96N=969.8≈10kgf and this force is towards mean position.The reaction of the force on the platform away from the mean position. It reduces the weight of man on upper extreme i.e. net weight = (60 - 10) kgf.This force adds to the weight at lower extreme position i.e. net weight becomes = (60 + 10) kgf.Therefore, the reading the weight recorded by spring balance fluctuates between 50 kgf and 70 kgf.