A man wishes to estimate the distance of a nearby tower from him. He stands at a point A in front of the tower C and spots a very distant object O in line with AC. He then walks perpendicular to AC upto B, a distance of $$100$$ m and looks at O and C again. Since O is very distant, the direction BO is practically the same as AO, but he finds the line of sight of C shifted from the original line of sight by angle θ$$=400$$ $$($$θ is known as $$parallax)$$, the distance of tower C from his original position A is

Question

A man wishes to estimate the distance of a nearby tower from him. He stands at a point A in front of the tower C and spots a very distant object O in line with AC. He then walks perpendicular to AC upto B, a distance of $$100$$ m and looks at O and C again. Since O is very distant, the direction BO is practically the same as AO, but he finds the line of sight of C shifted from the original line of sight by angle θ$$=400$$ $$($$θ  is  known  as  $$parallax)$$, the distance of tower C from his original position A is

Infinity Learn · Accepted Answer

Given, parallax angle θ$$=400From$$ the given figure,  $$AB=ACtan$$θ⇒$$AC=ABtan$$θ$$=100$$  $$mtan400=1000.8391=119$$  m

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