A man wishes to estimate the distance of a nearby tower from him. He stands at a point A in front of the tower C and spots a very distant object O in line with AC. He then walks perpendicular to AC upto B, a distance of 100 m and looks at O and C again. Since O is very distant, the direction BO is practically the same as AO, but he finds the line of sight of C shifted from the original line of sight by angle θ=400 (θ is known as parallax), the distance of tower C from his original position A is

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100 m

10 m

19 m

119 m

answer is D.

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Detailed Solution

Given, parallax angle θ=400From the given figure, AB=ACtanθ⇒AC=ABtanθ=100 mtan400=1000.8391=119 m

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