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A manometer connected to closed tap reads $3.5 \times 10^{5} N / m^{2}$ . When the valve is opened , the reading of manometer falls to $3 \times 10^{5} N / m^{2}$ , then velocity of flow of water is

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Correct option is B

Applying Bernoullie’s theorem we get,12v2=P1−P2ρ⇒v2=2×0.5×105103⇒v=10ms−1

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A manometer connected to closed tap reads 3.5×105N/m2. When the valve is opened , the reading of manometer falls to 3×105N/m2 , then velocity of flow of water is

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A manometer connected to closed tap reads $3.5 \times 10^{5} N / m^{2}$ . When the valve is opened , the reading of manometer falls to $3 \times 10^{5} N / m^{2}$ , then velocity of flow of water is