A manometer connected to a closed tap reads 3.5 × 105 N/m2. When the valve is opened, the reading of manometer falls to 3.0 × 105 N/m2, then velocity of flow of water is
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a
100 m/s
b
10 m/s
c
1 m/s
d
1010 m/s
answer is B.
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Detailed Solution
Bernoulli's theorem for unit mass of liquid Pρ+12v2= constant As the liquid starts flowing, it pressure energy decreases 12v2=P1−P2ρ⇒12v2=3.5×105−3×105103⇒v2=2×0.5×105103⇒v2=100⇒v=10 m/s