A manometer connected to a closed tap reads 4.5×105 pascal. When the tap is opened the reading of the manometer falls to 4×105 pascal. Then the velocity of flow of water is

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7 ms−1

8 ms−1

9 ms−1

10 ms−1

answer is D.

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Detailed Solution

P1−P2ρg=v22g⇒4.5×105−4×105103×g=v22g ∴v=10 m/s

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