First slide

Kinetic friction

Question

A marble block of mass 2 kg lying on ice when given a velocity of 6 $m s^{- 1}$ is stopped by friction in 10s. Then the coefficient of friction is (g = 10 $m s^{- 2}$ )

Moderate

A

0.02
B

0.03
C

0.06
D

0.01

Solution

0 = u - at ⇒ u = at = µg.t
$μ = \frac{v}{g t} = \frac{6}{10 \times 10} = 0.06$

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