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A mark is made on the bottom of a vessel and over this mark, a glass slab to thickness 3.5 cm and refractive index 74 is placed. Now water (refractive index.43) is poured into the vessel so that the surface of water is 8 cm above the upper surface of the slab. Looking down of normally through the water, the apparent depth of the mark below the surface of water will be :

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answer is 3.

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Detailed Solution

Using the relation apparent depth =real depthμ, we get apparent depth =3.57/5+84/3=(2+6)cm = 8 cm

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A mark is made on the bottom of a vessel and over this mark, a glass slab to thickness 3.5 cm and refractive index 74 is placed. Now water (refractive index.43) is poured into the vessel so that the surface of water is 8 cm above the upper surface of the slab. Looking down of normally through the water, the apparent depth of the mark below the surface of water will be :