In a marriage hall, there are 15 bulbs of 45 W,15 bulbs of 100 W,15 small fans of 10 W and 2 heaters of 1 kW. The voltage of electric main is 220 V. The minimum fuse capacity (rated value) of building will be

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

20 A

15 A

10 A

25 A

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Total power is(15×45)+(15×100)+(15×10) + (2 x 1000) = 4325 WSo current is =4325220=19.66AAns is 20 Amp

Watch 3-min video & get full concept clarity