First slide

Nuclear Binding energy

Question

The mass defect for the nucleus of Helium is 0.0303 amu. The binding energy per nucleon in MeV is nearly

Moderate

A

28
B

7
C

4
D

1

Solution

$BE = ∆ m x 931 MeV = 0.0303 x 931 MeV \frac{BE}{A} = \frac{0.0303 x 931}{4} = 7 MeV$

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