Q.

The mass defect for the nucleus of nitrogen is 0.0572 amu the binding energy per nucleon in Mev is nearly

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a

3.8

b

2.8

c

1.8

d

4.8

answer is A.

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Detailed Solution

BE per nucleon=BEA=(Δm)A×931Mev =0.0572×93114Mev =3.8038Mev
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