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Q.

The mass defect in a particular nuclear reaction is 0.3 grams. The amount of energy liberated in kilowatt hours is (Velocity of light = 3×108m/s )

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a

1.5×106

b

2.5×106

c

3×106

d

7.5×106

answer is D.

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Detailed Solution

E=Δm⋅c2⇒E=0.31000×3×1082=2.7×1013J =2.7×10133.6×106=7.5×106kWh
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