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Q.

The mass defect in a particular nuclear reaction is 0.3 grams. The amount of energy liberated in kilowatt hour is [Velocity of light = 3×108m/s ]

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a

1.5×106

b

2.5×106

c

3×106

d

7.5×106

answer is D.

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Detailed Solution

Δm=0.3×10−3kg E=Δmc2      =0.3×10−3×(3×108)2J     =0.3×9×101336×105kwH     =0.75×107     =7.5×106kwH
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