Questions
The mass and diameter of a planet are twice that of the earth. What will be the time period of oscillation of a pendulum on this planet, if it is a seconds pendulum on earth
detailed solution
Correct option is D
acceleration due to gravity on Earth is ge=GMR2 acceleration due to gravity on planet is gp=GMpRp2 Given radius of planet Rp=2Rearth=2Re given mass of planet Mp=2Mearth=2Megpge=GMpRp2×Re2GMe substitute values of Rp=2RE,MP=2Me gpge=2Re24Re2=12 gp=ge2 ........(1) TeTp=gpge=ge/2g=12 substitute time period on earth =2 that of seconds pendulum 2Tp=12⇒Tp=22 seconds.Talk to our academic expert!
Similar Questions
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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