Questions
The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If it is a second's pendulum on earth)
detailed solution
Correct option is B
As we know g=GMR2 ⇒gearthgplanet=MeMp×Rρ2Re2=Me2Me×4Re2Re2⇒gegp=21 Also T∝1g⇒TeTp=gpge⇒2Tp=12 ⇒Tp=22 sec.Talk to our academic expert!
Similar Questions
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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