The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If it is a second's pendulum on earth)
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a
12sec
b
22sec
c
2 sec
d
12sec
answer is B.
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Detailed Solution
As we know g=GMR2 ⇒gearthgplanet=MeMp×Rρ2Re2=Me2Me×4Re2Re2⇒gegp=21 Also T∝1g⇒TeTp=gpge⇒2Tp=12 ⇒Tp=22 sec.