First slide

Simple hormonic motion

Question

The mass and diameter of a planet are twice those of the earth. The period of oscillation of a pendulum on this planet will be, if it is a seconds pendulum on the earth 2.4 s

Easy

A

2.4 s
B

2.8 s
C

3.2 s
D

Infinity

Solution

$T = 2 π \sqrt{\frac{ℓ}{g}}; g = \frac{GM}{R^{2}}$

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