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Questions  

The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If it is a second's pendulum on earth)

a
12sec
b
22 sec
c
2 sec
d
12sec

detailed solution

Correct option is B

As we know g = GMR2⇒ gearthgplanet = MeMp×Rρ2Re2   ⇒ gegp = 21Also  T ∝ 1g   ⇒ TeTp = gpge   ⇒ 2Tp = 12⇒  Tp = 22sec

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