The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If it is a second's pendulum on earth)
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a
12sec
b
22 sec
c
2 sec
d
12sec
answer is B.
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Detailed Solution
As we know g = GMR2⇒ gearthgplanet = MeMp×Rρ2Re2 ⇒ gegp = 21Also T ∝ 1g ⇒ TeTp = gpge ⇒ 2Tp = 12⇒ Tp = 22sec