A mass of 100g strikes the wall with speed 5m/s at an angle as shown in figure and it rebounds with the same speed. If the contact time is 2×10−3 sec, what is the force applied on the mass by the wall

Force = Rate of change of momentum Initial momentum P→1=mvsinθ i^+mvcosθ j^Final momentum P→2=−mvsinθ i^+mvcosθ j^∴F→=ΔP→Δt=−2mvsinθ2×10−3Substituting m = 0.1 kg, v = 5 m/s, θ = 60°Force on the ball  F→=−2503NNegative sign indicates direction of the force