First slide

Collisions

Question

A mass of 100g strikes the wall with speed 5m/s at an angle as shown in figure and it rebounds with the same speed. If the contact time is $2 \times 10^{- 3} \sec$ , what is the force applied on the mass by the wall

Moderate

A

$250 \sqrt{3}$ N to right
B

250 N to right
C

$250 \sqrt{3}$ N to left
D

250 N to left

Solution

Force = Rate of change of momentum
Initial momentum ${\vec{P}}_{1} = mvsinθ \hat{i} + mvcosθ \hat{j}$
Final momentum ${\vec{P}}_{2} = - mvsinθ \hat{i} + mvcosθ \hat{j}$
$∴ \vec{F} = \frac{Δ \vec{P}}{Δt} = \frac{- 2 mvsinθ}{2 \times 10^{- 3}}$
Substituting m = 0.1 kg, v = 5 m/s, $θ$ = 60°
Force on the ball $\vec{F} = - 250 \sqrt{3} N$
Negative sign indicates direction of the force

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